From bbea82f7fe8af40fd08e8956e1aaf4d877168652 Mon Sep 17 00:00:00 2001 From: Ondřej Bílka Date: Wed, 30 Oct 2013 16:07:15 +0100 Subject: Remove code from div that is by C99 obsolete. Fixes bug 15799 --- stdlib/div.c | 22 ---------------------- 1 file changed, 22 deletions(-) (limited to 'stdlib/div.c') diff --git a/stdlib/div.c b/stdlib/div.c index 44a30a7ea4..0f5569a5dd 100644 --- a/stdlib/div.c +++ b/stdlib/div.c @@ -59,27 +59,5 @@ div (numer, denom) result.quot = numer / denom; result.rem = numer % denom; - /* The ANSI standard says that |QUOT| <= |NUMER / DENOM|, where - NUMER / DENOM is to be computed in infinite precision. In - other words, we should always truncate the quotient towards - zero, never -infinity. Machine division and remainer may - work either way when one or both of NUMER or DENOM is - negative. If only one is negative and QUOT has been - truncated towards -infinity, REM will have the same sign as - DENOM and the opposite sign of NUMER; if both are negative - and QUOT has been truncated towards -infinity, REM will be - positive (will have the opposite sign of NUMER). These are - considered `wrong'. If both are NUM and DENOM are positive, - RESULT will always be positive. This all boils down to: if - NUMER >= 0, but REM < 0, we got the wrong answer. In that - case, to get the right answer, add 1 to QUOT and subtract - DENOM from REM. */ - - if (numer >= 0 && result.rem < 0) - { - ++result.quot; - result.rem -= denom; - } - return result; } -- cgit v1.2.3